day5冒泡排序分分快三计划

作者:编程技术

[0, 0, 0, 0, 0]

  for index,i in enumerate(data[0:-1]):
  if i > data[index 1]:
    data[index 1],data[index] = i,data[index 1]
  print(data)
    运营如下:

    l[i] = 0

    上面来看看代码每趟运维的结果:

[0, 2, 4, 6, 8]

    上边的图是冒泡排序的法规,每一回循环把最大的值遍历到最前面,而且循环的历程中,每一遍循环的次数减1。

 

  data = [10,4,33,21,54,3,8,11,5,22,2,1,17,13,6]

for i in range(len(l)):

    分分快三计划 1

print (l)

  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]

运维结果:

  for j in range(len(data)):
    for i in range(len(data)-1):
      if data[i] > data[i 1]:
      tem = data[i 1]
      data[i 1] = data[i]
      data[i] = tem
  print(data)

二、在for循环中修正list值的艺术:

  结果是同等的,然而大家这边幸免了无数不供给的循环,大家看一下八个代码各自供给循环多少次,为此大家得以定义二个n在内部,每一次循环的时候加1。

print (l)

      tmp = data[index 1]
      data[index 1] = i
      data[index] = tmp

    l[index] = 0

    运维结果如下:

2.使用enumerate

    当然还会有豆蔻梢头种简易的法子能够完成列表的排序,并且只必要循环列表长度的次数就可以:

[0, 0, 0, 0, 0]

  能够见见是交换了岗位,可是是有不当的。13现身了两遍,22杀绝了,那是由于在循环进度中,我们转移了列表的下标,更动下标之后就涌出了错误,有个别值被交流了。因为不能如此做,恐怕下边那样也是老大的。

运行结果:

    运营代码结果如下:

    print (l)

  冒泡排序:是朝气蓬勃种根底的算法,达成数量的排序,排序的尺度是前三个与后叁个扩充相比较,若是前面的值大则调换,不然不交流,数次巡回每一次把最大的数据循环至后边就可见产生所需。

1.使用range

  下边代码中,大家的思绪是循环列表中的每种成分,前三个和后八个开展比较,借使前八个压倒后叁个就进展轮换,否则不动,这样每一遍把倒数最大值移到列表的末段,就会促成效果与利益,列表有稍许长度,大家就循环多少次,由此大家在外边步向了for循环,让下边包车型客车列表排序能够实行再三比较。可是上边的代码能够有一个更上后生可畏层楼的地点,我们领悟,每一遍循环都会把二个最大值放到列表的最后,因而循环的次数能够每便依次减少1次,上面大家对代码实行改革:

[0, 2, 4, 6, 8]

  for j in range(1,len(data)):
    for i in range(len(data)-j):
      if data[i] > data[i 1]:
        tem = data[i 1]
        data[i 1] = data[i]
        data[i] = tem
  print(data)

生机勃勃、在for循环中从来改变列表申月素的值不会起效果:

  data = [10,4,33,21,54,3,8,11,5,22,2,1,17,13,6]

如:

  for index,i in enumerate(data[0:-1]):
    if i > data[index 1]:
    #data[index 1],data[index] = i,data[index 1]
    #储存叁个临时变量用来存储消息

print (l)

    上面是布满每一遍运转的状态,上边是没一大步运维的景况:

print (l)

    data = [10,4,33,21,54,3,8,11,5,22,2,1,17,13,6]

l = list(range(10)[::2])

    print(data)

l中的成分并未被改进

  data = [10,4,33,21,54,3,8,11,5,22,2,1,17,13,6]
  numbers = []
  #探索列表中最小值的义务
  for i in range(len(data)):
    num = data.pop(data.index(min(data)))
    numbers.append(num)
  print(numbers)

    n = 0

  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]

for n in l:

  [4, 10, 21, 33, 3, 8, 11, 5, 22, 2, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 22, 2, 1, 17, 13, 6, 33, 54]
  [4, 10, 3, 8, 11, 5, 21, 2, 1, 17, 13, 6, 22, 33, 54]
  [4, 3, 8, 10, 5, 11, 2, 1, 17, 13, 6, 21, 22, 33, 54]
  [3, 4, 8, 5, 10, 2, 1, 11, 13, 6, 17, 21, 22, 33, 54]
  [3, 4, 5, 8, 2, 1, 10, 11, 6, 13, 17, 21, 22, 33, 54]
  [3, 4, 5, 2, 1, 8, 10, 6, 11, 13, 17, 21, 22, 33, 54]
  [3, 4, 2, 1, 5, 8, 6, 10, 11, 13, 17, 21, 22, 33, 54]
  [3, 2, 1, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [2, 1, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]

[0, 2, 4, 6, 8]

  [4, 10, 21, 33, 3, 54, 8, 5, 11, 2, 1, 2, 13, 6, 13]

 

    上边代码中tem的意义是积攒叁个data[index 1]因为大家掌握,要把data[index]和data[index 1]进展沟通,如若仅仅的沟通,有一个会被替换,因为要把被替换的值存在七个新的变量中,那样就制止了这种错误。

print (l)

    方法的原理是,大家清楚,目标是兑现列表桐月素的排序,那么大家每一趟找到列表中的最小值何况把这几个最小值使用pop方法弹出来,那么列表的长度每一趟减1,大家每回都只找小小值,使用index()查找值的目录,使用别的二个列表去选拔。就可见贯彻,运转结果如下:

运营结果:

  [4, 10, 33, 21, 54, 3, 8, 11, 5, 22, 2, 1, 17, 13, 6]
  [4, 10, 21, 33, 54, 3, 8, 11, 5, 22, 2, 1, 17, 13, 6]
  [4, 10, 21, 33, 3, 54, 8, 11, 5, 22, 2, 1, 17, 13, 6]
  [4, 10, 21, 33, 3, 8, 54, 11, 5, 22, 2, 1, 17, 13, 6]
  [4, 10, 21, 33, 3, 8, 11, 54, 5, 22, 2, 1, 17, 13, 6]
  [4, 10, 21, 33, 3, 8, 11, 5, 54, 22, 2, 1, 17, 13, 6]
  [4, 10, 21, 33, 3, 8, 11, 5, 22, 54, 2, 1, 17, 13, 6]
  [4, 10, 21, 33, 3, 8, 11, 5, 22, 2, 54, 1, 17, 13, 6]
  [4, 10, 21, 33, 3, 8, 11, 5, 22, 2, 1, 54, 17, 13, 6]
  [4, 10, 21, 33, 3, 8, 11, 5, 22, 2, 1, 17, 54, 13, 6]
  [4, 10, 21, 33, 3, 8, 11, 5, 22, 2, 1, 17, 13, 54, 6]
  [4, 10, 21, 33, 3, 8, 11, 5, 22, 2, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 33, 8, 11, 5, 22, 2, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 33, 11, 5, 22, 2, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 33, 5, 22, 2, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 33, 22, 2, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 22, 33, 2, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 22, 2, 33, 1, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 22, 2, 1, 33, 17, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 22, 2, 1, 17, 33, 13, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 22, 2, 1, 17, 13, 33, 6, 54]
  [4, 10, 21, 3, 8, 11, 5, 22, 2, 1, 17, 13, 6, 33, 54]
  [4, 10, 3, 21, 8, 11, 5, 22, 2, 1, 17, 13, 6, 33, 54]
  [4, 10, 3, 8, 21, 11, 5, 22, 2, 1, 17, 13, 6, 33, 54]
  [4, 10, 3, 8, 11, 21, 5, 22, 2, 1, 17, 13, 6, 33, 54]
  [4, 10, 3, 8, 11, 5, 21, 22, 2, 1, 17, 13, 6, 33, 54]
  [4, 10, 3, 8, 11, 5, 21, 2, 22, 1, 17, 13, 6, 33, 54]
  [4, 10, 3, 8, 11, 5, 21, 2, 1, 22, 17, 13, 6, 33, 54]
  [4, 10, 3, 8, 11, 5, 21, 2, 1, 17, 22, 13, 6, 33, 54]
  [4, 10, 3, 8, 11, 5, 21, 2, 1, 17, 13, 22, 6, 33, 54]
  [4, 10, 3, 8, 11, 5, 21, 2, 1, 17, 13, 6, 22, 33, 54]
  [4, 3, 10, 8, 11, 5, 21, 2, 1, 17, 13, 6, 22, 33, 54]
  [4, 3, 8, 10, 11, 5, 21, 2, 1, 17, 13, 6, 22, 33, 54]
  [4, 3, 8, 10, 5, 11, 21, 2, 1, 17, 13, 6, 22, 33, 54]
  [4, 3, 8, 10, 5, 11, 2, 21, 1, 17, 13, 6, 22, 33, 54]
  [4, 3, 8, 10, 5, 11, 2, 1, 21, 17, 13, 6, 22, 33, 54]
  [4, 3, 8, 10, 5, 11, 2, 1, 17, 21, 13, 6, 22, 33, 54]
  [4, 3, 8, 10, 5, 11, 2, 1, 17, 13, 21, 6, 22, 33, 54]
  [4, 3, 8, 10, 5, 11, 2, 1, 17, 13, 6, 21, 22, 33, 54]
  [3, 4, 8, 10, 5, 11, 2, 1, 17, 13, 6, 21, 22, 33, 54]
  [3, 4, 8, 5, 10, 11, 2, 1, 17, 13, 6, 21, 22, 33, 54]
  [3, 4, 8, 5, 10, 2, 11, 1, 17, 13, 6, 21, 22, 33, 54]
  [3, 4, 8, 5, 10, 2, 1, 11, 17, 13, 6, 21, 22, 33, 54]
  [3, 4, 8, 5, 10, 2, 1, 11, 13, 17, 6, 21, 22, 33, 54]
  [3, 4, 8, 5, 10, 2, 1, 11, 13, 6, 17, 21, 22, 33, 54]
  [3, 4, 5, 8, 10, 2, 1, 11, 13, 6, 17, 21, 22, 33, 54]
  [3, 4, 5, 8, 2, 10, 1, 11, 13, 6, 17, 21, 22, 33, 54]
  [3, 4, 5, 8, 2, 1, 10, 11, 13, 6, 17, 21, 22, 33, 54]
  [3, 4, 5, 8, 2, 1, 10, 11, 6, 13, 17, 21, 22, 33, 54]
  [3, 4, 5, 2, 8, 1, 10, 11, 6, 13, 17, 21, 22, 33, 54]
  [3, 4, 5, 2, 1, 8, 10, 11, 6, 13, 17, 21, 22, 33, 54]
  [3, 4, 5, 2, 1, 8, 10, 6, 11, 13, 17, 21, 22, 33, 54]
  [3, 4, 2, 5, 1, 8, 10, 6, 11, 13, 17, 21, 22, 33, 54]
  [3, 4, 2, 1, 5, 8, 10, 6, 11, 13, 17, 21, 22, 33, 54]
  [3, 4, 2, 1, 5, 8, 6, 10, 11, 13, 17, 21, 22, 33, 54]
  [3, 2, 4, 1, 5, 8, 6, 10, 11, 13, 17, 21, 22, 33, 54]
  [3, 2, 1, 4, 5, 8, 6, 10, 11, 13, 17, 21, 22, 33, 54]
  [3, 2, 1, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [2, 3, 1, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [2, 1, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]
  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]

for index,value in enumerate(l):

  data = [10,4,33,21,54,3,8,11,5,22,2,1,17,13,6]

l = list(range(10)[::2])

    下边来看三个实例,大家将二个列表data = [10,4,33,21,54,3,8,11,5,22,2,1,17,13,6],大家将列表举行排序。代码如下:

[0, 2, 4, 6, 8]

    首先收取列表的依次和下表enumerate(

l = list(range(10)[::2])

  [1, 2, 3, 4, 5, 6, 8, 10, 11, 13, 17, 21, 22, 33, 54]

    data = [10,4,33,21,54,3,8,11,5,22,2,1,17,13,6]
  n = 0
  for j in range(len(data)):
  #for j in range(1,len(data)):
    for i in range(len(data)-1):
    #for i in range(len(data) - j):
    n = n 1
    if data[i] > data[i 1]:
      tem = data[i 1]
      data[i 1] = data[i]
      data[i] = tem
  print(n)
  print(data)

    经过地点二种方法的测量检验,未有改正的点子运营了2十遍,修改之后的主意值运营了105次,可知超级多时候修改一小点就会省去点不清时光。

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